Physics, asked by jayeshbagaria46, 10 months ago

The error in the measurement of radius of a sphere is 2 percent. What would be the error in the volume of sphere?

Answers

Answered by mufeedhapc256

4

Answer:

6%

Explanation:

$volume \alpha {r}^{3}$

therefore,

% error in volume

=3×% error in radius

=3×2

=6%

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