Question

The error in the measurement of radius of a sphere
is 2%, then the error in determination of volume of
the sphere will be
(1) 8%
(2) 2%
(3) 4%
(476%​

Answer 1

Volume of sphere =4/3(pi)r^3

error in volume is

dv/v=3(dr/r)

given error in radius=dr/r=2%

hence dv/v=3(2%)=6%