Question

The error in the measurement of radius of a sphere
is 2%, then the error in determination of volume of
the sphere will be
(1) 8%
(2) 2%
(3) 4%
(4) 6%​

Answer 1

нєуα❤❤

Error=2%

So,
∆r/r × 100 = 2

∆r / r = 2 / 100

As, volume of sphere = 4/3 π r ^3

∆v / v = 3 ∆r/ r

= 3 × 2 / 100

= 6/100

So, % error = ∆ v/v × 100

= 6/100× 100

= 6%

ANS : 4) 6%

Hope helps..❤❤❤❤

Answer 2

Answer :-

Given :-

Measurment error in the radius = 2%

To find :-

Measurment error in volume of sphere

Solution :-

Volume of sphere = 4/3 πr³

Measurment error in sphere = 3 (Measurment error in the radius)

= 3 ( 2% )

= 6 %

Measurment error in volume of sphere = 6%