Question

The error in the measurement of radius of a sphere is 2%.What would be the error in the volume of the
sphere?
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Answer 1

Explanation:

Percentage error in radius is given as 2% i.e.  rΔr×100=2 %

Volume of sphere   V=34πr3

Percentage error in volume   VΔV×100=3×rΔr×100=3×2=6 %