Physics, asked by akshay7359, 1 year ago

the error in the measurement of radius of sphere is 2% . what could be the error in the volume of the sphere

Answers

Answered by snehkadyan14

1

Answer:

6%

Explanation:

%error in radius=∆r/r×100

=2%

volume of sphere=4/3πr3

error in volume =3×∆r/r×100

=3×2%

=6%

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