the error in the measurement of the potential difference across the end of the conducting wire is 5% and the measurement of the current is 2% what will be the percentage error in calculating its resistance
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Error in V=5%
and in I=2%
as R=V/I
thus, percentage error in R = power*percentage error in V+percentage error in I
R%=5%+2%
=7%
and in I=2%
as R=V/I
thus, percentage error in R = power*percentage error in V+percentage error in I
R%=5%+2%
=7%
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