Math, asked by jananishri16, 1 month ago

the error in the measurement of the radius of a sphere is 1% what is the error in the measurement?

Answers

Answered by DaLgOnA

28

Answer:

3%

Step by step explanation:

Volume= 4πR³ / 3

ΔV/ VV×100 = 3 ΔR/R ×100

= 3× 1/100 ×100 =3

∴Percentage error in volume is 3%

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