Physics, asked by sahumamata457, 6 months ago

The error in the measurement of the
radius of a sphere is 2%, what is
percentage error in the measurement
of the volume ? :

Answers

Answered by heartbeat22

0

Explanation:

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Answered by romandave425

2

Explanation:

Δr/r = 2percent

volume = 4/3 pie r^3

volume = (Δr/r)^3

= (2)^3

= 8

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