The escape velocity for a body projected vertically upwards from the surface of earth is 11km/s . if the body is projected at an angle 45°. with the vertical , then the escape velocity with be . [AIEEE 2003]
Answers
Answered by
2
Answer:
Escape speed of a body from Earth's surface is given by: vmin = √2gR
This expression is obtained by conservation of energy and doesn't involve in which direction the body is thrown/projected.
So, irrespective of the angle of projection, escape speed of the body from Earth's surface remains constant i.e. ≈11 km/s
HOPING THIS WILL HELP YOU PLZ MARK AS BRAINLIEST AND FOLLOW ME
Answered by
2
Answer:
11
Explanation:
The escape velocity is independent of angle of projection , hence it will remain same i.e 11km/s
____________________________________
Similar questions