Question

The escape velocity for a body projected vertically upwards from the surface of earth is 11km/s . if the body is projected at an angle 45°. with the vertical , then the escape velocity with be . [AIEEE 2003] ​

Answer 1

Answer:

Escape speed of a body from Earth's surface is given by: vmin = √2gR

This expression is obtained by conservation of energy and doesn't involve in which direction the body is thrown/projected.

So, irrespective of the angle of projection, escape speed of the body from Earth's surface remains constant i.e. ≈11 km/s

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Answer 2

Answer:

11

Explanation:

The escape velocity is independent of angle of projection , hence it will remain same i.e 11km/s

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