The escape velocity from earth is 11.2 km/s. If a
body is to be projected in a direction making an
angle 45° to the vertical, then the escape velocity
is
(a) 11.2 × 2 km/s (b) 11.2 km/s
(c) 11.2 / √2 km/s (d) 11. 2 √2 km/s
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Answer:
As we learnt in
Escape velocity -
Minimum velocity which is required to escape the body from earth's gravitational pull
- wherein
It is independent of the mass and direction of projection of body.
Escape velocity is independent of direction of projection. Hence it will remain same for all direction.
V_{e}=11.2 km/sec
Option 1)
11.2 × 2 km/sec
This is incorrect option
Option 2)
11.2 km/sec
This is correct option
Option 3)
11.2\times \frac{1}{\sqrt{2}}\, \, \, \, \, Km/sec
This is incorrect option
Option 4)
11.2\times \sqrt{2} \, \, \, Km/sec
This is incorrect option
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