Physics, asked by juhiiii802, 9 months ago

The escape velocity from earth is 11.2 km/s. If a
body is to be projected in a direction making an
angle 45° to the vertical, then the escape velocity
is
(a) 11.2 × 2 km/s (b) 11.2 km/s
(c) 11.2 / √2 km/s (d) 11. 2 √2 km/s

Answers

Answered by deepakbhai1814
1

Answer:

As we learnt in  

Escape velocity -

Minimum velocity which is required to escape the body from earth's gravitational pull

- wherein

It is independent of the mass and direction of projection of body.

 

Escape velocity is independent of direction of projection. Hence it will remain same for all direction.

V_{e}=11.2 km/sec

Option 1)

11.2 × 2 km/sec

This is incorrect option

Option 2)

11.2 km/sec

This is correct option

Option 3)

11.2\times \frac{1}{\sqrt{2}}\, \, \, \, \,  Km/sec

This is incorrect option

Option 4)

11.2\times \sqrt{2} \, \, \, Km/sec

This is incorrect option

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