Math, asked by shruti142005, 4 months ago

The Escape velocity from the Earth for a body of 20 g is 11.2 km/s. What will be its value for a body of 100 g?​

Answers

Answered by hassan2952l
21

Answer:

100 ÷ 20 = 5

11.2 × 5 = 56 km/s

Escape velocity is independent of the mass of the projected body provided the air resistance is neglected. Hence, the escape velocity of 10kg10kg of the iron ball projected from the earth is same that of escape velocity of 10g10g projected from the earth

Answered by rishkrith123
0

Answer:

The escape velocity from the earth for a body of mass of 100 g is 11.2 Km/s.

Step-by-step explanation:

Given,

The escape velocity from the Earth for the body of mass m1 = 20 g is (v) = 11.2 km/s.

To find,

The escape velocity for a body of mass m2 = 100 g (V) is?

Calculation,

We know that the escape velocity from the Earth of the body depends only on:

  • the square root of acceleration due to the gravity of the celestial body (a).
  • the square root of the radius of the celestial body (R)

i.e. Escape velocity (u) = √(gR)

Now if the celestial body is earth then:

u = 11.2 Km/s

Hence, for a body with a mass of 20 g or a body with a mass of 100 g the escape velocity for a particular celestial body remains the same.

Therefore, the escape velocity from the earth for a body of mass of 100 g is 11.2 Km/s.

#SPJ3

Similar questions