Physics, asked by anniev2015, 7 months ago

The escape velocity from the earth’s surface is 11 km/sec. A certain planet has a radius twice that of the earth but its mean density is the same as that of the earth. The value of the escape velocity from this planet would be

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Answered by ashokkumar6394
0

Explanation:

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Answered by richajain55
0

Explanation:

Solution :

Let

be the mass radius and density of earth and

be the corresponding vaues of the planet. Then escape speed from earth's surface is <br>

<br> Escape speed from planet's surface is <br>

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