The escape velocity of a body depends on mass of the body, radius of earth and acceleration due to gravity. Derive an expression for escape velocity using dimension analysis
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Answer:
Explanation:
v = k gᵃ Rᵇ
where, k= dimensionless constant.
now
[v] = [ gᵃ Rᵇ ]
[L T ⁻¹] = [(LT ⁻²)ᵃ Lᵇ]
By getting the values of L and T equalized on both sides we will get
a + b = 1
or
-1 = -2a
a = ½
b = ½
Therefore v ∝ (gR)½
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