Physics, asked by jnitheesh266, 3 days ago

the escape velocity of a rocket from the surface of the Earth is v., then the escape velocity of the same rocket from the surface of a planet whose acceleration due to gravity as well as radius are 3 times that of the Earth is​

Answers

Answered by yashshreemore2910
0

Answer:

Ans: 3V or 33.6

Explanation:

Vesc= √2GM/ R

Hence escape velocity will become thrice

Vesc for earth is 11.2

Therefore, for planet Vesc = 11.2× 3= 33.6

i.e. 3V

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