the escape velocity of a rocket from the surface of the Earth is v., then the escape velocity of the same rocket from the surface of a planet whose acceleration due to gravity as well as radius are 3 times that of the Earth is
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Answer:
Ans: 3V or 33.6
Explanation:
Vesc= √2GM/ R
Hence escape velocity will become thrice
Vesc for earth is 11.2
Therefore, for planet Vesc = 11.2× 3= 33.6
i.e. 3V
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