Question

the escape velocity of mass is 5.02 km/sec . if its radius is 3390 km ,what is the value of g on its surface

Answer 1

Answer:

GRAVITATION

Explanation:

★ ESCAPE VELOCITY (Ve)★

GIVEN ;

♠ ESCAPE VELOCITY = 5.02 Km / s

♣ Radius = 3390 km

♥ g ( acceleration due to gravity ) = ???

♦ ON SURFACE .....

★ Ve = √ 2 × g × R

» 5.02 × 10³ = √ 2 × g × 3390 × 10³

» 5.02 × 10³ = √ 678 g × 10⁴

★ Squaring both the sides ; we get

» 25.2 × 10^6 = 678 × 10⁴ × g

» g = 25.2 × 10^6 / 678 × 10⁴

» g = 25200 × 10³ / 6780 × 10³

» g = 3.71 m / s²

ANSWER :- HENCE ; FOR RADIUS 3390 km ;

Acceleration due to Gravity ( g ) = 3.71 m /s².

★ THIS VALUE IS NOT FOR EARTH ★

→EARTH ( g ) = 9.8 m / s²←