the exam scores of all 500 students were recorded and it was determined that these scores were normally distributed. If jane’s score is 0.8 standard deviation above the mean,then how many,to the nearest until,students scored above jane?
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Answered by
4
Answer:
multiply it
Step-by-step explanation:
hope it helps you
Answered by
7
Answer:
106
Step-by-step explanation:
s be the standard deviation and find the z score.
z= =0.8
The percentage of student who scored above Jane is (from the table of normal distribution)=1−0.7881=0.2119=21.19 percentage
The number of students who scored above Jane is (from the table of normal distribution)
=21.19% of 500= 21.19×5 = 106
@request Mark my answer as brainiest.
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