The exam scores of all 500 students were recorded and it was determined that these scores were normally distributed.If Janes score is 0.8standard deviation above the mean, then how many, to the nearest until,students stored above Jane?
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Answer:
106 students
Step-by-step explanation:
The exam scores of all 500 students were recorded and it was determined that these scores were normally distributed.If Janes score is 0.8standard deviation above the mean, then how many, to the nearest until,students stored above Jane?
Z score = ( score - Mean) / Standard deviation
=> Z score = ( Mean + 0.8 Standard deviation - Mean)/Standard deviation
=> Z score = 0.8 Standard deviation/Standard deviation
=> z score = 0.8
z score 0.8 = 78.81 % ( see attached z score table)
Number of students who scored more than Jane = 100 - 78.81%
= 21.19 %
21.19 % of 500
= (21.19/100) * 500
= 105.95
= 106
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