Physics, asked by deepakkiran6665, 1 year ago

The excess pressure across a soap bubble of radius r is p=4sigma/r where sigma is the surface tension of soap solution what is tge excess pressure across an air bubble of the same radius f formed inside a container of soap solution

Answers

Answered by Fatimakincsem
1

The excess pressure across an air bubble of the same radius r formed inside a container of soap solution is 2σ/r.

Explanation:

  • A soap bubble has two surfaces while floating in air.
  • Whereas air bubble has only one surface in the solution of soap.
  • Therefore air bubble has half of the excess pressure of soap bubble in air in soap solution.

Thus

= 1/2  ×   4σ/r

= 2σ/r

Hence the excess pressure across an air bubble of the same radius r formed inside a container of soap solution is 2σ/r.

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