The excess pressure inside a soap bubble is equal
to an oil column of height 3 mm. The total surface
area of the soap bubble in contact with air will be
(given, density of oil = 0.9 g/cm3, surface tension
of soap solution
solution = 0.03 N/m and g = 10 ms-2)
6.
[NCERT Pg. 268]
(2) 1.24 x 10-4 m2
(1) 4.96 * 10-4 m2
(3) 3.72 x 104 m2
(4) 1.03 * 104 m2
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0
Answer:
Explanation:
Correct option is
C
8:1
Outside pressure = 1 atm
Pressure inside first bubble = 1.01 atm
Pressure inside second bubble = 1.02 atm
Excess pressure ΔP
1
=1.01−1=0.01 atm
Excess pressure ΔP
2
=1.02−1=0.02 atm
ΔP∝
r
1
⇒r∝
ΔP
1
⇒
r
2
r
1
=
ΔP
1
ΔP
2
=
0.01
0.02
=
1
2
Since, V=
3
4
πr
3
∴
V
2
V
1
=(
r
2
r
1
)
3
=(
1
2
)
3
=
1
8
Answer
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