Question

The excess pressure inside a soap bubble is twice the excess pressure inside a second soap bubble.the volume of the first bubble is n times the volume of the second bubble.find the value of n.

Answer 1

4T/$r_1$= 2×4T/$r_2$ or $r_2$ = $2r_1$

4/3π$r^3_1$ = n×4/3π$r^3_2$ = n×4/3π($2r_1$)³ or n= 1/8 = 0.125