Question

The excluded value of (x+1)/5x(2x+2)​

Answer 1

SOLUTION

TO DETERMINE

The excluded value of

$\displaystyle\sf{ \frac{(x + 1)}{5x(2x + 2)} }$

EVALUATION

Let f(x) be the given function

Then

$\displaystyle\sf{ f(x) = \frac{(x + 1)}{5x(2x + 2)} }$

We now simplify the function as below

$\displaystyle\sf{ f(x) = \frac{(x + 1)}{5x(2x + 2)} }$

$\displaystyle\sf{ \implies \: f(x) = \frac{(x + 1)}{5x.2(x + 1)} }$

$\displaystyle\sf{ \implies \: f(x) = \frac{(x + 1)}{10x(x + 1)} }$

$\displaystyle\sf{ \implies \: f(x) = \frac{1}{10x} }$

The function is not well defined where the denominator vanishes

Denominator = 10x

Now denominator vanishes when 10x = 0

Thus we get x = 0

Hence the required excluded value is 0

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