Question

The exit gage distribution in a stirred reactor is given bye t e 1 t/ . Fluid elements e1 and e2 enter the reactor at times t = 0 and t = 0 > 0, respectively. The probability that e2 exits the reactor before e1 is (a) 1 / 2 (b) 1 2 e- / (c) e- / (d) zero.

Answer 1

Answer:

D.

Explanation:

Because anything you solve against zero will result 0