Chemistry, asked by lydia6133, 1 year ago

The experimental value of the dipole moment of hcl is 1.03



d. The length of the h-cl bond is 1.275 å. The percentage of ionic character in hcl is

Answers

Answered by Rajnav
102

If HCl molecule is 100% ionic it will dissociate as follows

HCl->(H+)+(Cl-)

In that case the dipole moment will be

µ = 4.8 × 10^-10 esu × 1.275× 10&^-8cm

µ= 6.12 × 10^-18 esu cm

µ=6.12D

IONIC CHARACTER = (1.03/6.12)×100%

IONIC CHARACTER = 16.83% Ans

Please hit thank you if the answer is correct .

Answered by cjooijoklkl
6

Answer:

17% ionic

83% covalent

hope it helps

goodbye

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