Question

The explanation for how a beta particle is produced in the nucleus of a radionuclide and then ejected involves the conversion (in a complex series of steps) of a 1 punto b) electron and neutron c) proton to an electron. a)proton to a neutron. d) neutron to an electron.​

Answer 1

Answer:

In nuclear physics, beta decay (β-decay) is a type of radioactive decay in which a beta particle (fast energetic electron or positron) is emitted from an atomic nucleus, transforming the original nuclide to an isobar of that nuclide. For example, beta decay of a neutron transforms it into a proton by the emission of an electron accompanied by an antineutrino; or, conversely a proton is converted into a neutron by the emission of a positron with a neutrino in so-called positron emission. Neither the beta particle nor its associated (anti-)neutrino exist within the nucleus prior to beta decay, but are created in the decay process. By this process, unstable atoms obtain a more stable ratio of protons to neutrons. The probability of a nuclide decaying due to beta and other forms of decay is determined by its nuclear binding energy. The binding energies of all existing nuclides form what is called the nuclear band or valley of stability.[1] For either electron or positron emission to be energetically possible, the energy release (see below) or Q value must be positive.

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