Question

The expression 16(x-y)(4a-b)+12(x-y)(a+4b) can be factorised as

Answer 1

Answer:

Take (x-y) common

(x-y){16(4a-b)+12(a+4b)}

=4(x-y){4(4a-b)+3(a+4b)}

=4(x-y){16a-4b+3a+14b}

=4(x-y)(19a+10b) Ans

Answer 2

Step-by-step explanation:

8x-3=9-2x

8x+2x=9+3

10x=12

x=12\10

x=6\5

7-5x=5-7x

7-5=-7x+5x

2=-2x

2\-2=x

-2\2=x

-1=x

3+2x=1-x

2=-x-2x

2=-3x

2\-3=x

-2\3=x

x=-2\3

2(x-2+3(4x-1)=6

2x-4+12x-3=6

14x-4-3=6

14x-7=6

14x=6+7

14 x=13

x=13\14

5(2x-3)-3(3x-7)=5

10x-15-9x+21=5

x-15+21=5

x=5-6

x=-1