The expression 2^6n - 4^2n, where n is the natural number is always divisble by ?
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in such type of question
if it is given that n belongs to natural number then simply put n = 1,2. . . etc
in the given equation by putting n = 1
we have
2^6 - 4^2
=> 64 - 16
=> 48
which is answer
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