Question

The expression 3(x^2)-mx+10 leaves a remainder of -2 when divided by x-3. What's the value of m?

Answer 1

Answer:

Step-by-step explanation: Given, 3.x.x - m.x + 10 leaves remainder of -2    when divided by x-3

Let p(x)= 3x² - mx + 10

and, g(x)= x-1

         0   = x-1

         x   = 1

now put the value of x in p(x)

p(1)= 3×1×1 - m×1 + 10

As we know remainder is -2 we will take p(1) as -2

-2 = 3 - m + 10

-2 - 13 = -m

-15 = -m

m=13

This is the problem of the chapter  polynomials.

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Answer 2

Answer:

Step-by-step explanation:

Given, 3.x.x - m.x + 10 leaves remainder of -2    when divided by x-3

Let p(x)= 3x² - mx + 10

and, g(x)= x-1

        0   = x-1

        x   = 1

now put the value of x in p(x)

p(1)= 3×1×1 - m×1 + 10

As we know remainder is -2 we will take p(1) as -2

-2 = 3 - m + 10

-2 - 13 = -m

-15 = -m

m=13