Question

the expression(5^-1+7^-1+3^-1)^0 is equal to

Answer 1

Answer:

the answer is 1.

I hope it helps u

Answer 2

Answer:

= $(5 {}^{ - 1} + 7 {}^{ - 1} + 3 {}^{ - 1} ) {}^{0}$

= $( \frac{1}{5} + 7 {}^{ - 1} + 3 {}^{ - 1} ) {}^{0}$

= $( \frac{1}{5} + \frac{1}{7} + 3 {}^{ - 1} ) {}^{0}$

= $( \frac{1}{5} + \frac{1}{7} + \frac{1}{3} )<em> </em>{}^{0}$

= $( \frac{71}{105} ) {}^{0}$

= $1$

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