the expression by which (3a--4)is to be multiplied to get a difference of two cubes is
please help me to solve this
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Answer:
(9a²+12a-16)
Step-by-step explanation:
We know,
(a³-b³) = (a-b) (a²+ab-b²)
considering RHS
(a-b) =(3a-4)
hence, a=3a & b=4
therefore, (a²+ab-b²)= (9a²+12a-16)
thus, (3a-4) is to be multiplied by (9a²+12a-16) to express it as a difference of two cubes, namely (27a³-64).
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