Question

the expression of 2^6n-4^2n where n is natural number always devisble by​

Answer 1

Answer:

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Answer 2

Answer:

2 and 1

Step-by-step explanation:

6n = even

2^6n = 2^even = even

2n = even

4^2n = 4^even = even

Now 2^6n-4^2n is basically even - even which gives even. Thus, it should always be divisible by 2