Computer Science, asked by sahilkumar5815832, 6 months ago

The expression within the parenthesis are evaluated first *​

Answers

Answered by sayamkapoor
2

Answer:

Expressions within parentheses are evaluated first. When parentheses are nested, the innermost set of parentheses is evaluated first, and then successively more inclusive parentheses are evaluated.

Answered by gunduravimudhiraj76
0

Answer:

What is the correct sequence of the math operations in this expression in Java:

a + b * c / ( d - e )

1. 4 1 3 2

2. 4 2 3 1

I understand that result is the same in both answers. But I would like to fully understand the java compiler logic. What is executed first in this example - multiplication or the expression in parentheses? A link to the documentation that covers that would be helpful.

UPDATE: Thank you guys for the answers. Most of you write that the expression in parentheses is evaluated first. After looking at the references provided by Grodriguez I created little tests:

int i = 2;

System.out.println(i * (i=3)); // prints '6'

int j = 2;

System.out.println((j=3) * j); // prints '9'

Could anybody explain why these tests produce different results? If the expression in parentheses is evaluated the first I would expect the same result - 9.

Explanation:

as you as helpful as mark me as brainlest

Similar questions