Question

The expression [(x - y)(x +y) + (y - z)(y + z) + (z - x)(z + x)] after simplification becomes

Answer 1

Answer:

= 0

Step-by-step explanation:

= [(x - y)(x +y) + (y - z)(y + z) + (z - x)(z + x)]

= [(x²+y²) + (y²-z²) + (z²-x²)]

= [x²+y² + y²-z² + z²-x²]

= [x²-x² +y²-y² +z²-z²]

= 0 ans