Physics, asked by Raja3776, 11 months ago

The extension of a wire by the application of load is 3 mm. The extension in a wire of the same material and length but half the radius by the same load is

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Answered by AbdJr10
5

Answer:

so

elongation \: in \: length =  \frac{f \times l}{y \times \pi {r}^{2} }  \\ elongation \: is \: inversly \: propotional \: to \:  {r}^{2}  \\  \frac{3 \times  {10}^{ - 3} }{x}  =  \frac{ \frac{ {r}^{2} }{4} }{ {r}^{2} }  \\ x = 12mm

hope the answer will help you

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