Math, asked by rishuraj529, 7 months ago

The extension of an elastic spring is found to vary directly with the weight
suspended from it. If a weight of 75 kg produces an extension of 1.4 cm,
calculate the weight that would produce an extension of 9.8 cm.​

Answers

Answered by anshika9289
0

Answer

the extension of an elastic spring found to vary directly with the weight

the extension of an elastic spring found to vary directly with the weightsuspended from it

the extension of an elastic spring found to vary directly with the weightsuspended from itso write

the extension of an elastic spring found to vary directly with the weightsuspended from itso writelaw

the extension of an elastic spring found to vary directly with the weightsuspended from itso writelaw=> 1 = kw (1)

the extension of an elastic spring found to vary directly with the weightsuspended from itso writelaw=> 1 = kw (1)where k = proportionality constant

the extension of an elastic spring found to vary directly with the weightsuspended from itso writelaw=> 1 = kw (1)where k = proportionality constant|= represent the extension of an elastic spring

the extension of an elastic spring found to vary directly with the weightsuspended from itso writelaw=> 1 = kw (1)where k = proportionality constant|= represent the extension of an elastic springw=represent the weight

the extension of an elastic spring found to vary directly with the weightsuspended from itso writelaw=> 1 = kw (1)where k = proportionality constant|= represent the extension of an elastic springw=represent the weightw = 75kg

the extension of an elastic spring found to vary directly with the weightsuspended from itso writelaw=> 1 = kw (1)where k = proportionality constant|= represent the extension of an elastic springw=represent the weightw = 75kg1.4 cm

the extension of an elastic spring found to vary directly with the weightsuspended from itso writelaw=> 1 = kw (1)where k = proportionality constant|= represent the extension of an elastic springw=represent the weightw = 75kg1.4 cmso substitute these vale In equation (1)

the extension of an elastic spring found to vary directly with the weightsuspended from itso writelaw=> 1 = kw (1)where k = proportionality constant|= represent the extension of an elastic springw=represent the weightw = 75kg1.4 cmso substitute these vale In equation (1)we have 1.4 = kx 75

the extension of an elastic spring found to vary directly with the weightsuspended from itso writelaw=> 1 = kw (1)where k = proportionality constant|= represent the extension of an elastic springw=represent the weightw = 75kg1.4 cmso substitute these vale In equation (1)we have 1.4 = kx 75k=1.4/ 75

the extension of an elastic spring found to vary directly with the weightsuspended from itso writelaw=> 1 = kw (1)where k = proportionality constant|= represent the extension of an elastic springw=represent the weightw = 75kg1.4 cmso substitute these vale In equation (1)we have 1.4 = kx 75k=1.4/ 75so equation (1) becomes

the extension of an elastic spring found to vary directly with the weightsuspended from itso writelaw=> 1 = kw (1)where k = proportionality constant|= represent the extension of an elastic springw=represent the weightw = 75kg1.4 cmso substitute these vale In equation (1)we have 1.4 = kx 75k=1.4/ 75so equation (1) becomes1 =1.4/75 W

the extension of an elastic spring found to vary directly with the weightsuspended from itso writelaw=> 1 = kw (1)where k = proportionality constant|= represent the extension of an elastic springw=represent the weightw = 75kg1.4 cmso substitute these vale In equation (1)we have 1.4 = kx 75k=1.4/ 75so equation (1) becomes1 =1.4/75 Wwhen I= 9.8 cm = 1.4 / 75 x w

the extension of an elastic spring found to vary directly with the weightsuspended from itso writelaw=> 1 = kw (1)where k = proportionality constant|= represent the extension of an elastic springw=represent the weightw = 75kg1.4 cmso substitute these vale In equation (1)we have 1.4 = kx 75k=1.4/ 75so equation (1) becomes1 =1.4/75 Wwhen I= 9.8 cm = 1.4 / 75 x w=> w = 9.8 x 75/1.4 = 525 kg

the extension of an elastic spring found to vary directly with the weightsuspended from itso writelaw=> 1 = kw (1)where k = proportionality constant|= represent the extension of an elastic springw=represent the weightw = 75kg1.4 cmso substitute these vale In equation (1)we have 1.4 = kx 75k=1.4/ 75so equation (1) becomes1 =1.4/75 Wwhen I= 9.8 cm = 1.4 / 75 x w=> w = 9.8 x 75/1.4 = 525 kghence w = 525 kg, I= 9.8 cm

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