The exterior angle ACD of a triangle ABC is 105º. If angle B = 70°, find A. Is angle ACD > angle A? Find angle ACB also.
Answers
The exterior angle ACD of a triangle ABC is 105º. If angle B = 70°, find A. Is angle ACD > angle A? Find angle ACB also.
Find A :
By using the formula of-
Exterior angle of the triangle is equal to the sum of öpposite ïnterior angles of the triangle.
Exterior angle = 150°
First opposite interior angle = 70°
Let the second interior angle be x
Second öpposite interior angle = x
Now,
So, the second interior angle = x = 80° = A
Is angle ACD > angle A? :
Find angle ACB :
By using the formula of-
Sum of all angles on straight line is equal to 180°
Let angle ACB be y
Angles on straight line are angle ACD (150°) and angle ACB (y)
Now,
So, angle ACB = y = 30°
Another method of finding angle ACB :
By using the formula of-
Sum of all interior angles in a triangle is equal to 180°
First Angle = angle ABC = 70°
Second angle = angle BAC = 80°
Let angle ACB be y
Third angle = angle ACB = y
Now,
So, angle ACB = y = 30°