The exterior angle of a regular polygon is 1/3rd of its interior angle. Find the no. of the polygon.
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The sum of the interior and exterior angle of any polygon at any vertex is equal to 180°.
Let x = the exterior angle.
3x+x = 180
4x = 180
x=45
The sum of all exterior angles of any polygon is 360°.
∴ 360/45=8
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Let x = the exterior angle.
3x+x = 180
4x = 180
x=45
The sum of all exterior angles of any polygon is 360°.
∴ 360/45=8
please mark me as BRAINLIEST
himanshu5136:
please mark me as brainliest
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