The exterior angle of pentagon are in the ratio 6:3:4:3:2. Find all it's interior angle
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let the exterior angles of the Pentagon be 6x,5x,4x,3xand2x
we know that sum of all exterior angles of a Pentagon is360°
=6x+5x+4x+3x+2x=360
=20x=360
=X=360/20
=18
the angles are 6x,5x,4x,3x,2x
=6*18,5*18,4*18,3*18,2*18
=108,90,72,54,36
interior angle=180-exterior angle
=180-108=72
=180-90=90
=180-72=108
=180-54=126
=180-36=144
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