the exterior angle PRS of triangle PQR is 105degrees. if q= 70degrees, find angleP. is anglePRS greater than angleP
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yashusri what do you found wrong in this
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Answered by
41
in triangle PQR,
angle Q = 70 degree
angle PRS = 105 dergrees
let angle QRP be angle 1, then;
angle 1+ 105 degree = 180 degree (linear pair)
angle 1 = (180 - 105) degrees
= 75 degree
now, since we have angle Q = 70 degree, and
angle 1 = 75 degree
let the unknown angle i.e. angle P be x degrees
now, angle (Q + 1 + x) = 180 degrees (angle sum proplerty of a triangle)
(70 + 75 + x) degrees = 180
(145 + x )degrees = 180
x = (180 - 145)
= 35 degrees
therefore angle P = 35°
angle Q = 70 degree
angle PRS = 105 dergrees
let angle QRP be angle 1, then;
angle 1+ 105 degree = 180 degree (linear pair)
angle 1 = (180 - 105) degrees
= 75 degree
now, since we have angle Q = 70 degree, and
angle 1 = 75 degree
let the unknown angle i.e. angle P be x degrees
now, angle (Q + 1 + x) = 180 degrees (angle sum proplerty of a triangle)
(70 + 75 + x) degrees = 180
(145 + x )degrees = 180
x = (180 - 145)
= 35 degrees
therefore angle P = 35°
Answered by
52
∠PRS=105°
∠PQR=70°
we know that ,
exterior angle of a triangle is equal to sum 2 opposite angles in a triangle
⇒∠PRS=∠PQR+∠QPR
⇒105°=70°+∠QPR
⇒∠QPR=35°
∠PQR=70°
we know that ,
exterior angle of a triangle is equal to sum 2 opposite angles in a triangle
⇒∠PRS=∠PQR+∠QPR
⇒105°=70°+∠QPR
⇒∠QPR=35°
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