The exterior angles obtained on producing the base of a triangle both ways are 100° and 120°. Find all the angles
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ANSWER:-
Given:
The exterior angles obtained on producing the base of a ∆ boths way are 100° & 120°.
To find:
Find all the angles.
Solution:
Let, ABC be a triangle & base BC produced to both sides. Exterior angles are ∠ABD & ∠ACE.
Therefore,
⏺️∠ABD = 100°
⏺️∠ACE = 120°
We know that, linear pair of ∆;
=) ∠ABD + ∠ABC = 180°
=) ∠ABC = 180° - ∠ABD
=) ∠ABC = 180° - 100°
=) ∠ABC = 80°
&
∠ACE + ∠ACB = 180° [Linear pair]
=) 120° + ∠ACB= 180°
=) ∠ACB= 180° -120°
=) ∠ACB= 60°
So,
In ∆ABC,
∠A + ∠B+ ∠C= 180°
=) ∠A + 80° + 60° = 180°
=) ∠A + 140° = 180°
=) ∠A = 180° -140°
=) ∠A= 40°
Thus,
angles of ∆ are 40°, 80° & 60°.
Hope it helps ☺️
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