Question

the exterior angles obtained on producing the base of a triangle bothy ways are 100°and 110° find all the angles of a triangle​

Answer 1

Answer:

It is given that the interior opposite angles are equal i.e., ∠A=∠B.

∴ Equation (1) becomes

2∠A=100o

⇒∠A=50o

⇒∠B=50o

Using angle sum property of a triangle,

Sum of all angles of a triangle =180o

⇒∠A+∠B+∠C=180o

⇒100+∠C=180o [from (1)]

⇒∠C=180o−100o

⇒∠C=80o.

Hence ∠A=50o

∠B=50o

∠C=80o.