The exterior angles obtained on producing the base of a triangle both ways are 104 degree and 136 degree find all the angles of the triangle
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From the adjacent figure,
the exterior angle ∠ACD=136°
∴, ∠ACB=180°-136°=44°
the other exterior angle, ∠ABE=104°
∴, ∠ABC=180°-104°=76°
∴, ∠BAC=180°-(∠ABC+∠ACB)
=180°-(76°+44°)
=180°-120°
=60°
∴, the angles of the given triangle are: 76°,60° and 44° Ans.
the exterior angle ∠ACD=136°
∴, ∠ACB=180°-136°=44°
the other exterior angle, ∠ABE=104°
∴, ∠ABC=180°-104°=76°
∴, ∠BAC=180°-(∠ABC+∠ACB)
=180°-(76°+44°)
=180°-120°
=60°
∴, the angles of the given triangle are: 76°,60° and 44° Ans.
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In triangle ABC, Let the base angles be angle B and angle C.
angle B = 180-104 = 76 degrees
angle C = 180-136 = 44 degrees
Therefore,
The third angle, that is, angle A = 180 - (76+44) = 180 - 120 = 60 degrees.
Hence,
The angles of the triangle are 60 degree, 76 degree and 44 degree
angle B = 180-104 = 76 degrees
angle C = 180-136 = 44 degrees
Therefore,
The third angle, that is, angle A = 180 - (76+44) = 180 - 120 = 60 degrees.
Hence,
The angles of the triangle are 60 degree, 76 degree and 44 degree
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