the exterior angles of a pentagon are in the ratio 1:2:3:4:5.find all interior angles of a pentagon
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hry
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Answered by
22
heya..mate here's ur answer
we know that all the exterior angles of a Pentagon sum up to 360°
so let all the angles be x..
so therefore 1x+2x+3x+4x+5x=360°
so 15x=360°
therefore x=24°
2x=48°
3x=72°
4x=96°
5x=120°
so the interior angles will be
180°-24=156°
180-48=132°
180-72=108°
180-96=84°
180-120=60°
we know that all the exterior angles of a Pentagon sum up to 360°
so let all the angles be x..
so therefore 1x+2x+3x+4x+5x=360°
so 15x=360°
therefore x=24°
2x=48°
3x=72°
4x=96°
5x=120°
so the interior angles will be
180°-24=156°
180-48=132°
180-72=108°
180-96=84°
180-120=60°
Answered by
9
let all anges be x, 2x,3x,4x,5x.
x+2x+3x+4x+5x=360°
15x=360°
x=360÷15
x= 24
x= 24°
2x=24×2=48°
3x=24×3=72°
4x=24×4=96°
5x=24×5=120°
now, subtract them all from 180 for interior angles
x+2x+3x+4x+5x=360°
15x=360°
x=360÷15
x= 24
x= 24°
2x=24×2=48°
3x=24×3=72°
4x=24×4=96°
5x=24×5=120°
now, subtract them all from 180 for interior angles
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