the exterior angles of a pentagon are thr ratio 1:2:3:4:5. Find all the interior angles of a pentagon.
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Sum of exterior angles of pentagon is equal to 360
So, let us assume the angles of the pentagon be 1a,2a,3a,4a and 5a.
1a+2a+3a+4a+5a=360
15a=360
a=360 /15
a=24
Therefore, the angles of pentagon are, 1a=1×24=24
2a=2×24=48
3a=3×24=72
4a=4×24=96
5a=5×24=120
Then, interior angles of the pentagon are, 180 - 24 =156
180 - 48 =132
180 - 72 =108
180 - 96 =84
180 - 120 =60
So, let us assume the angles of the pentagon be 1a,2a,3a,4a and 5a.
1a+2a+3a+4a+5a=360
15a=360
a=360 /15
a=24
Therefore, the angles of pentagon are, 1a=1×24=24
2a=2×24=48
3a=3×24=72
4a=4×24=96
5a=5×24=120
Then, interior angles of the pentagon are, 180 - 24 =156
180 - 48 =132
180 - 72 =108
180 - 96 =84
180 - 120 =60
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