The exterior angles of a quadrilateral are (x+20),(x+10),(2x-45) and(x-25/. Find the value of x
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Since, sum of exterior angles of a quadrilateral = 360°
Given,angles are (x+20),(x+10),(2x-45),(x-25)
(x+10)+(x+20)+(2x-45)+(x-25) = 360°
5x-40° = 360°
5x = 360° + 40°
x = 400/5 =. 80°
Value of x is 80°
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Other angles are 100° , 90° , 115 ° , 55° .
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