Question

The exterior angles of a quadrilateral are (x+20),(x+10),(2x-45) and(x-25/. Find the value of x

Answer 1

Since, sum of exterior angles of a quadrilateral = 360°

Given,angles are (x+20),(x+10),(2x-45),(x-25)

(x+10)+(x+20)+(2x-45)+(x-25) = 360°

5x-40° = 360°

5x = 360° + 40°

x = 400/5 =. 80°

Value of x is 80°

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Answer 2

Other angles are 100° , 90° , 115 ° , 55° .

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