Question

the exterior diameter of a hollow tube 2m long is 6cm.If the thickness is 1cm,find the volume of the solid part(in cubic cm)​

Answer 1

Answer:

Let external diameter be d2 and internal be d1

⇒d2=8cm & d1=8−1−1=6cm

Therefore, r1=3cm & r2=4cm

Volume of hollow cylindrical pipe=π(r22−r12)×h

=722((4)2−(3)2)×21

=722×7×21

=462cm3

∴Weight of the pipe=8×462=3696g=3.696kg