the exterior diameter of a hollow tube 2m long is 6cm.If the thickness is 1cm,find the volume of the solid part(in cubic cm)
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Answer:
Let external diameter be d2 and internal be d1
⇒d2=8cm & d1=8−1−1=6cm
Therefore, r1=3cm & r2=4cm
Volume of hollow cylindrical pipe=π(r22−r12)×h
=722((4)2−(3)2)×21
=722×7×21
=462cm3
∴Weight of the pipe=8×462=3696g=3.696kg
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