The external and internal diameter of a hollow hemispherical bowl are 12 cm and 10 cm respectively .find the cost of painting. It all over at the rate of 2 per sq.cm
Answers
Answered by
2
area of inner curve surface of bowl=2pir^2
area of outer curve surface of bowl=2pi.R^2
so total area =2pi. (r^2+R^2)
=2 x 22/7 x (25+36)=44/7 x 61
cost of painting=44/7 x 61 x 2=767Rs (approx)
area of outer curve surface of bowl=2pi.R^2
so total area =2pi. (r^2+R^2)
=2 x 22/7 x (25+36)=44/7 x 61
cost of painting=44/7 x 61 x 2=767Rs (approx)
Similar questions