Question

the external angle ACD of a triangle ABC is 105 Angle B is 70 degree find angle A is greater question mark find a b c also​

Answer 1

AnSwEr

As, two opposite angle of a triangle =1 exterior angle

Therefore, angle B + angle A = angle ACD

70°+angle A = 105°

Angle A= 105-70 = 35°

Now,

Angle (A+B+C)= 180°

70+35+angle C = 180

angle C =180-70-35

Angle C = 180-105 = 75°

Therefore, angle ACB = 75°

Answer 2

The question wasn't clear but I tried my level best to comprehend it and answer

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