Question

The external dimension of an open rectangular wooden box are 98cm,84cm,77cm if the wood is 2 CM thick all around find i) internal dimension II) capacity iii) volume of wood iv) weight of the box in kg given that 0.8gm

Answer 1

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Answer 2

Given external dimensions i.e. length, breadth, height of the box are 98 cm, 84 cm, 77 cm respectively.

Internal dimensions would be

length  = 98-2-2 = 94 cm

breadth = 84-2-2 = 80 cm

height = 77-2-2 = 73 cm

The Capacity of the box would be internal volume of box i.e.

V = 94*80*73 =548960 cm³

The volume of wood would be equal to external volume - internal volume i.e.

98*84*77 - 94*80*73 =  84904 cm³

weight of the box would be equal to volume * density = 84904* 0.8 gm = 67923.2 gm = 67 kg