the external dimensions of an open iron box 32cm 22 cm and 16 cm if the thickness of iron is 1 cm find the volume of the iron used
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Step-by-step explanation:
external dimensions = 32cm 22cm and 16cm.
thickness is 1cm
internal dimensions = Volume of iron box = 31cm 21cm 15cm = 9765cm³
Volume of iron used = Volume of box - Area of rectangle (because it is open box)
= 9765cm³ - (l*b)
= 9765 - (31*21)
= 9765 - 651
= 3114cm³
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