The external length, breadth and height of a closed rectangular wooden box are 20 cm, 12 cm and 6 cm respectively and thickness of wood is 0.5 cm. Find the volume of wood.
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QUESTION :-
➠ The external length, breadth and height of a closed rectangular wooden box are 20 cm, 12 cm and 6 cm respectively and thickness of wood is 0.5 cm. Find the volume of wood.
ANSWER :-
➠ Let
•external length of the closed box → L •external breadth of the closed box → B •external height of the closed box → H
so ,
- L = 20 cm,
- B = 12 cm,
- H = 6 cm
➠ Let
•internal length of the closed box → l •internal breadth of the closed box → b •internal height of the closed box → h
so ,
- l = [20 – (2 × 0.5)] cm 19 cm
- b = [12 (2 × 0.5)] cm = 11 cm
- h = [6 - (2 x 0.5)] cm = 5 cm
➠ External volume of the box
→ L × B x H
→ (20 × 12 × 6) cm³
→ 1440 cm³
➠ External volume of the box
→ l × b × h
→ (19 × 11 × 5) cm ³
→ 1045 ³
➠Volume of wood = External volume Internal volume
→ (1440 - 1045) cm ³
Answered by
1
Step-by-step explanation:
l × b ×h
20 × 12 × 6
1440
l × b × h
19 × 11 × 5
1045 cm
1440 -1045
395 cm
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